A) 400
B) 300
C) 200
D) 500
Correct Answer: B
Solution :
Speed of train = 60 kmph \[=\left( 60\times \frac{5}{18} \right)\] m/sec. \[=\frac{50}{3}\] m/sec. If the length of platform be \[=x\] metre, then Speed of train \[=\frac{Length\text{ }of\text{ }\left( train\text{ }+\text{ }platform \right)}{Time\text{ }taken\text{ }in\text{ }crossing}\] \[\Rightarrow \]\[\frac{50}{3}=\frac{200+x}{30}\] \[\Rightarrow \] \[50\times 10=200+x\] \[\Rightarrow x=500-200=300\] metreYou need to login to perform this action.
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