A) 5
B) 8
C) 3
D) 4
Correct Answer: D
Solution :
Work done by A and B in first 6 days = (A + B)'s 4 days' work +B?s 2 days' work \[=4\times \frac{1}{8}+\frac{2}{12}\] \[=\frac{1}{2}+\frac{1}{6}=\frac{3+1}{6}=\frac{4}{6}=\frac{2}{3}\] Remaining work \[=1-\frac{2}{3}=\frac{1}{3}\] \[\therefore \]Time taken by C \[=\frac{1}{3}\times 12=4\] daysYou need to login to perform this action.
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