A) 4
B) 2
C) 6
D) 8
Correct Answer: A
Solution :
\[16\Rightarrow {{(2+2)}^{2}}={{(4)}^{2}}\] \[9\Rightarrow {{(3+0)}^{2}}={{(3)}^{2}}\] \[81\Rightarrow {{(1+8)}^{2}}={{(9)}^{2}}\] Similarly, \[64\Rightarrow {{(4+4)}^{2}}={{(8)}^{2}}\]
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