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SSC Sample Paper SSC (Group-C) Sample Test Paper-10

  • question_answer
    A is faster than B. A and B each walk 24 km. The sum of their speeds is \[7\text{ }km/hr\]and the sum of times taken by them is 14 hours. Then A's speed is equal to:

    A)  \[3\text{ }km/hr.\]                  

    B)  \[4\text{ }km/hr.\]

    C)  \[5\text{ }km/hr.\]                  

    D)  \[7\text{ }km/hr.\]

    Correct Answer: B

    Solution :

     Let, A's speed\[=x\text{ }kmph\]. \[\therefore \] B's speed \[=(7-x)\] kmph Time \[=\frac{\text{Distance}}{Speed}\] According to the question, \[\frac{24}{x}+\frac{24}{7-x}=14\] \[\Rightarrow \]            \[24\left( \frac{7-x+x}{x(7-x)} \right)=14\] \[\Rightarrow \]            \[\frac{24\times 7}{x(7-x)}=14\] \[\Rightarrow \]            \[x(7-x)=12=4\times 3\] or \[3\times 4\] \[\Rightarrow \]            \[x(7-x)=4(7-4)\] or \[(7-3)\] \[\Rightarrow \]            \[x=4\] or 3 \[\therefore \]  A's speed\[=4\text{ }kmph\].


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