A) Rs.1000
B) Rs.2000
C) Rs.1500
D) Rs.2500
Correct Answer: B
Solution :
Let the principal be Rs. P. \[\therefore \] \[A=P{{\left( 1+\frac{R}{100} \right)}^{T}}\Rightarrow 2420=P{{\left( 1+\frac{10}{100} \right)}^{2}}\] \[\Rightarrow \,\,2420=P\times {{\left( 1+\frac{10}{100} \right)}^{2}}\Rightarrow 2420=P{{\left( \frac{11}{10} \right)}^{2}}\] \[\Rightarrow \,\,P=\frac{2420\times 10\times 10}{11\times 11}=Rs.\,2000\]
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