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SSC Sample Paper SSC (Group-C) Sample Test Paper-3

  • question_answer
    Two numbers are in the ratio\[1\frac{1}{2}\,\,:\,\,2\frac{2}{3}\]. When each of these is increased by 15, they are in the ratio\[1\frac{1}{2}\,\,:\,\,2\frac{2}{3}\]. The greater of the numbers is

    A)  27                

    B)  36

    C)  48                

    D)  64

    Correct Answer: C

    Solution :

     First number \[=\frac{3x}{2}\]and second number \[=\frac{8x}{3}\] According to the question, \[\frac{\frac{3x}{2}+15}{\frac{8x}{3}+15}=\frac{\frac{5}{3}}{\frac{5}{2}}\] \[\Rightarrow \] \[\frac{\frac{3x+30}{2}}{\frac{8x+45}{3}}=\frac{5}{3}\times \frac{2}{5}=\frac{2}{3}\] \[\Rightarrow \] \[\frac{(3x+30)\times 3}{(8x+45)\times 2}=\frac{2}{3}\] \[\Rightarrow \] \[32x+180=27x+270\] \[\Rightarrow \] \[32x-27x=270-180\] \[\Rightarrow \] \[5x=90\] \[\Rightarrow \] \[x=\frac{90}{5}=18\] \[\therefore \] Larger number \[=\frac{8x}{3}=\frac{8\times 18}{3}=48\]


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