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SSC Sample Paper SSC (Group-C) Sample Test Paper-3

  • question_answer
    A and B work together to complete the rest of a job in 7 days. However, \[\frac{37}{100}\]- of the job was already done. Also. The work done by A in 5 days is equal to the work done by B in 4 days. How many days would be required by the faster worker to complete the entire work?

    A)  20                 

    B)  25

    C)  30                 

    D)  10

    Correct Answer: A

    Solution :

     Remaining work \[=1-\frac{37}{100}\] \[=\frac{100-37}{100}=\frac{63}{100}\] \[\therefore \] Time taken by (A + B) in doing \[\frac{63}{100}\] part of work = 7 days \[\therefore \] Time taken by them in doing whole work \[=\frac{100}{63}\times 7=\frac{100}{9}\] days Respective ratio of time taken by A and B in doing the work \[=5:4\] \[\therefore \] \[\frac{1}{4x}+\frac{1}{5x}=\frac{9}{100}\] \[\Rightarrow \] \[\frac{5+4}{20x}=\frac{9}{100}\] \[\Rightarrow \] \[20x=100\Rightarrow \,x=5\] \[\therefore \] Required time \[=4\times 5=20\] days


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