A) 27
B) 36
C) 48
D) 64
Correct Answer: C
Solution :
First number \[=\frac{3x}{2}\]and second number \[=\frac{8x}{3}\] According to the question, \[\frac{\frac{3x}{2}+15}{\frac{8x}{3}+15}=\frac{\frac{5}{3}}{\frac{5}{2}}\] \[\Rightarrow \] \[\frac{\frac{3x+30}{2}}{\frac{8x+45}{3}}=\frac{5}{3}\times \frac{2}{5}=\frac{2}{3}\] \[\Rightarrow \] \[\frac{(3x+30)\times 3}{(8x+45)\times 2}=\frac{2}{3}\] \[\Rightarrow \] \[32x+180=27x+270\] \[\Rightarrow \] \[32x-27x=270-180\] \[\Rightarrow \] \[5x=90\] \[\Rightarrow \] \[x=\frac{90}{5}=18\] \[\therefore \] Larger number \[=\frac{8x}{3}=\frac{8\times 18}{3}=48\]You need to login to perform this action.
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