A) \[s{{p}^{2}}\] and \[s{{p}^{2}}\]
B) \[s{{p}^{3}}\] and sp
C) sp and \[s{{p}^{2}}\]
D) sp and sp
Correct Answer: C
Solution :
[c] \[{{C}^{1}}\] has \[2\sigma -\] and \[2\pi -\]bonds (sp hybridized). \[{{C}^{2}}\] has \[3\sigma \] and \[1\,\pi -\]bond (\[s{{p}^{2}}\]hybridized). Note hybridized orbitals never form \[\pi -\]bonds.
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