A) \[B{{F}_{3}}>N{{H}_{3}}>N{{F}_{3}}\]
B) \[B{{F}_{3}}>N{{F}_{3}}>N{{H}_{3}}\]
C) \[N{{H}_{3}}>B{{F}_{3}}>N{{F}_{3}}\]
D) \[N{{H}_{3}}>N{{F}_{3}}>B{{F}_{3}}\]
Correct Answer: D
Solution :
[d] Both \[N{{F}_{3}}\] and \[N{{H}_{3}}\] have identical shape and a lone pair of electrons on nitrogen. The dipole moment of \[N{{H}_{3}}\] is higher than \[N{{F}_{3}}\] due to different directions of moments of the N - F and N - H bond. BF is a symmetrical molecule. It has zero dipole moment.
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