A) \[NO_{2}^{+}\] and \[Ba{{O}_{2}}\]
B) \[K{{O}_{2}}\]and \[AlO_{2}^{-}\]
C) \[K{{O}_{2}}\] only
D) \[Ba{{O}_{2}}\] only
Correct Answer: C
Solution :
[c] In \[N{{O}_{2}}^{+}\] odd (unpaired) electron is removed. In peroxides \[({{O}_{2}}^{2-})\] no unpaired electrons are persent as the antibonding pi M.O.'s acquired one more electron each for pairing. \[AlO_{2}^{-}\] containing \[A{{l}^{3+}}(2{{s}^{2}}{{p}^{6}})\] configuration and 2 oxides \[({{O}^{2-}})\] ions each of which does not contain unpaired electron. Superoxide \[O_{2}^{-}\] has one unpaired electron in pi antibonding M.O.
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