JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Sample Paper Topic Test - Chemical Equilibrium

  • question_answer
    Correct equilibrium constant expression for the reaction is \[H{{C}_{2}}{{H}_{3}}{{O}_{2}}+{{H}_{2}}O{{H}_{3}}{{O}^{+}}+{{C}_{2}}{{H}_{3}}O_{2}^{-}\]

    A) \[{{K}_{a}}=\frac{[{{C}_{2}}{{H}_{3}}O_{2}^{-}][{{H}_{3}}{{O}^{+}}]}{[H{{C}_{2}}{{H}_{3}}{{O}_{2}}]}\]

    B) \[{{K}_{a}}=\frac{[{{C}_{2}}{{H}_{3}}O_{2}^{-}]}{[H{{C}_{2}}{{H}_{3}}{{O}_{2}}]}\]

    C) \[{{K}_{a}}=\frac{[{{C}_{2}}{{H}_{3}}O_{2}^{-}][{{H}_{3}}{{O}^{+}}]}{[H{{C}_{2}}{{H}_{3}}{{O}_{2}}][{{H}_{2}}O]}\]

    D) \[{{K}_{a}}=\frac{[{{C}_{2}}{{H}_{3}}O_{2}^{-}]}{[H{{C}_{2}}{{H}_{3}}{{O}_{2}}][{{H}_{2}}O]}\]

    Correct Answer: A

    Solution :

    [a] In equilibrium constant expression pure liquid concentration is not incorporated while the concentration of aqueous form is considered.


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