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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Sample Paper Topic Test - Chemical Equilibrium

  • question_answer
    The equilibrium constant \[{{K}_{c}}\] for the reaction \[{{P}_{4}}(g)2{{P}_{2}}(g)\] is 1.4 at \[400{}^\circ C.\] Suppose that 3 moles of \[{{P}_{4}}(g)\] and 2 moles of \[{{P}_{2}}(g)\] are mixed in 2 litre container at \[400{}^\circ C.\]. What is the value of reaction quotient (Q)?

    A) \[\frac{3}{2}\]

    B) \[\frac{2}{3}\]

    C) 1

    D) None of these

    Correct Answer: B

    Solution :

    [b] \[{{Q}_{C}}=\frac{{{[{{P}_{2}}(g)]}^{4}}}{[{{P}_{4}}(g)]}=\frac{{{(1)}^{2}}}{(3/2)}=\frac{2}{3}\]


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