A) 150 s
B) 200 s
C) 240 s
D) 210 s
Correct Answer: D
Solution :
| \[cis-Xtrans-X\] | |||||||||
| \[{{K}_{(aq)}}=\frac{{{k}_{f}}}{{{k}_{b}}};{{k}_{b}}=\frac{3\times {{10}^{-4}}}{0.1}=3\times {{10}^{-3}}\] | |||||||||
| |||||||||
| \[\left( {{k}_{f}}+{{k}_{b}} \right)=\frac{1}{t}\ln \,\left( \frac{{{x}_{e}}}{{{x}_{e}}-x} \right)\] | |||||||||
| Given \[x=\frac{{{x}_{e}}}{2}\] | |||||||||
| \[\therefore \] \[\,\left( {{k}_{f}}+{{k}_{b}} \right)=\frac{1}{2}\ln 2\] | |||||||||
| or \[\left( 3\times {{10}^{-3}}+3\times {{10}^{-4}} \right)=\frac{0.693}{t}\] | |||||||||
| \[t=210s\] |
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