For the reaction \[A+2B\to \] products(started with concentrations taken in stoichiometric proportion), the experimentally determined rate law is \[-\frac{d[B]}{dt}=k\sqrt{[A]}\sqrt{[B]}\] |
The half time of the reaction would be |
A) \[\frac{\sqrt{2}\times 0.693}{k}\]
B) \[\frac{0.693}{1/k}\]
C) \[\frac{0.693}{\sqrt{2}k}\]
D) not defined
Correct Answer: A
Solution :
A | + | 2B\[\xrightarrow{{}}\]Product | |
a | 2a | 0 | |
a - x | 2a - 2x | x |
You need to login to perform this action.
You will be redirected in
3 sec