A) \[1.57\times {{10}^{14}}Lmo{{l}^{-1}}{{s}^{-1}}\]
B) \[3.14\times {{10}^{15}}Lmo{{l}^{-1}}{{s}^{-1}}\]
C) \[1.57\times {{10}^{7}}Lmo{{l}^{-1}}{{s}^{-1}}\]
D) \[3.14\times {{10}^{10}}Lmo{{l}^{-1}}{{s}^{-1}}\]
Correct Answer: B
Solution :
| \[{{k}_{eq}}=\frac{{{k}_{1}}}{{{k}_{b}}}=\frac{{{[C{{H}_{3}}]}^{2}}}{[{{C}_{2}}{{H}_{6}}]}\] |
| \[[C{{H}_{3}}]=\frac{{{10}^{-5}}}{10}mol{{L}^{-1}}={{10}^{-6}}mol{{L}^{-1}}\] |
| \[[{{C}_{2}}{{H}_{6}}]=\frac{100}{10}=10mol{{L}^{-1}}=10M\] |
| \[{{k}_{eq}}=\frac{{{k}_{f}}}{{{k}_{b}}}\] |
| \[\frac{{{[{{10}^{-6}}]}^{2}}}{10}=\frac{3.14\times {{10}^{2}}{{s}^{-1}}}{{{k}_{b}}}\] |
| \[{{k}_{b}}=3.14\times {{10}^{3+12}}Lmo{{l}^{-1}}{{s}^{-1}}\] |
| \[=3.14\times {{10}^{15}}Lmo{{l}^{-1}}{{s}^{-1}}\] |
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