| Given |
| (i) \[Mn{{O}_{4}}^{-}+8{{H}^{+}}+5{{e}^{-}}\xrightarrow{{}}\]\[M{{n}^{2+}}+4{{H}_{2}}\,O\] |
| (ii) \[Mn{{O}_{2}}+4{{H}^{+}}+2{{e}^{-}}\xrightarrow{{}}\]\[M{{n}^{2+}}+2{{H}_{2}}\,O{{E}^{0}}={{x}_{2}}V\] |
| Find \[{{E}^{0}}\] for the following reaction |
| \[Mn{{O}_{4}}^{-}+4{{H}^{+}}+3{{e}^{-}}\xrightarrow{{}}Mn{{O}_{2}}+2{{H}_{2}}\,O\] |
A) \[{{x}_{2}}-{{x}_{1}}\]
B) \[{{x}_{1}}-{{x}_{2}}\]
C) \[\frac{5{{x}_{1}}-2{{x}_{2}}}{3}\]
D) \[\frac{2{{x}_{1}}-5{{x}_{2}}}{3}\]
Correct Answer: C
Solution :
[c]| \[\Delta G_{1}^{0}=-5{{x}_{1}}F\] | ; | \[\Delta G_{2}^{0}=-2{{x}_{2}}F\] |
| \[\Delta G_{3}^{0}=\Delta G_{1}^{0}-\Delta G_{2}^{0}\] | ; | \[\Delta G_{3}^{0}=2{{x}_{2}}F-5{{x}_{1}}F\] |
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