A block of mass 10 kg is kept on the fixed incline having coefficient of friction 0.8. Find the force of friction exerted on the block by inclined: |
A) 100 N
B) 64 N
C) 80 N
D) 60 N
Correct Answer: D
Solution :
Friction required \[=\,\,mg\,\sin \,37{}^\circ \] |
\[=10\times 10\times \frac{3}{5}=60\,N\] |
Maximum friction provided \[=\mu \,mg\,\cos \,37{}^\circ \] |
\[=0.8\times 10\times 10\times \frac{4}{5}=64\,\,N\] |
So friction force will be 60 N. |
You need to login to perform this action.
You will be redirected in
3 sec