question_answer

A fireman of mass 60 kg slides down a pole. He is pressing the pole with a force of 600 N. The coefficient of friction between the hands and the pole is 0.5. With what acceleration will the fireman slide down?

A) \[1\,\,m/{{s}^{2}}\]                 

B) \[2.5\,\,m/{{s}^{2}}\]

C) \[10\,\,m/{{s}^{2}}\]               

D) \[5\,\,m/{{s}^{2}}\]

Correct Answer: D

Solution :

Friction =\[\mu \,R=0.5\times 600=300\,N\]

Weight = 600 N

\[ma=W-F\Rightarrow a=\frac{W-F}{m}=\frac{600-300}{60}\]

\[a=5\,m/{{s}^{2}}\]