A) \[32{}^\circ C\]
B) \[27{}^\circ C\]
C) \[37{}^\circ C\]
D) \[30.5{}^\circ C\]
Correct Answer: A
Solution :
| [a] Let t is the temperature of mixture. |
| Heat gained by \[C{{O}_{2}}=\] Heat lost by \[{{O}_{2}}\] |
| \[\Rightarrow \] \[{{\mu }_{1}}{{C}_{{{v}_{1}}}}\Delta {{T}_{1}}={{\mu }_{2}}{{C}_{{{v}_{2}}}}\Delta {{T}_{2}}\] |
| \[\Rightarrow \] \[\frac{22}{44}(3R)\,(t-27)=\frac{16}{32}\left( \frac{5}{2}R \right)\,(37-t)\] |
| \[\Rightarrow \] \[3(t-27)\,=\frac{5}{2}\,(37-t)\] |
| By solving, we get \[t={{32}^{o}}C\] |
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