A) Curve 1 shows acceleration against time
B) Curve 2 shows velocity against time
C) Curve 2 shows velocity against acceleration
D) none of these
Correct Answer: D
Solution :
[d] \[G=\alpha t,\] \[ma=\alpha t\Rightarrow a\,\propto \,t\] curve 1 is a against time \[\frac{mdv}{dt}=\alpha t\]. Integrating this we get \[v\,\propto \,{{t}^{2}}\] this implies parabola. Also \[v\,\propto \,{{\alpha }^{2}}\Rightarrow \] curve 3 shows velocity against acceleration.
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