JEE Main & Advanced Chemistry Classification of Elements and Periodicity in Properties / तत्त्वों का वर्गीकरण एवं गुणों में आवर्ति Sample Paper Topic Test - Periodic Table

  • question_answer
    The atomic numbers of vanadium (V), chromium (Cr), manganese (Mn) and iron (Fe) are, respectively 23, 24, 25 and 26. Which one of these may be expected to have the highest second ionisation enthalpy?

    A) V     

    B) Cr

    C) Mn    

    D) Fe

    Correct Answer: B

    Solution :

    [b]
    \[F{{e}^{+}}(26)=[Ar]\text{ }3{{d}^{6}},\,\,4{{s}^{1}}\]
    \[M{{n}^{+}}\text{(}25\text{)}=[Ar]3{{d}^{5}}\text{ }4{{s}^{1}}\]
    \[{{V}^{+}}\text{(}23\text{)}=[Ar]\text{ }3{{d}^{2}}\text{ }4{{s}^{2}}\]
    \[C{{r}^{+}}\text{(}24\text{)}=[Ar]\text{ }3{{d}^{5}}\text{ }4{{s}^{0}}\]
    (By first IP) The electronic configuration of \[C{{r}^{+}}\] is most stable, hence formation of \[C{{r}^{2+}}\] by second IP requires maximum enthalpy.


You need to login to perform this action.
You will be redirected in 3 sec spinner