JEE Main & Advanced Chemistry Classification of Elements and Periodicity in Properties / तत्त्वों का वर्गीकरण एवं गुणों में आवर्ति Sample Paper Topic Test - Periodic Table

  • question_answer
    How many elements would be in the second period of the Periodic Table if the spin quantum number \[{{m}_{s}}\] could have the value \[-\frac{1}{2},\,0,\,+\frac{1}{2}\]?

    A) 8

    B) 10           

    C) 12

    D) 18

    Correct Answer: C

    Solution :

    [c] For second period \[n=2\] hence
    I m \[{{m}_{s}}\]
    0 0 \[+\frac{1}{2},\,\,0,\,-\frac{1}{2}\]
    1 - 1 \[+\frac{1}{2},\,0,\,-\frac{1}{2}\]
    0 1 \[+\frac{1}{2},\,0,\,-\frac{1}{2}\]
    +1   \[+\frac{1}{2},\,0,\,-\frac{1}{2}\]
    Hence, total number of elements = 12 (= total values of spin quantum number)


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