A) \[\underline{N}{{O}_{2}}\] and \[{{\underline{N}}_{2}}{{O}_{4}}\]
B) \[{{\underline{P}}_{2}}{{O}_{5}}\] and \[{{\underline{P}}_{4}}{{O}_{10}}\]
C) \[{{\underline{N}}_{2}}O\] and \[\underline{N}O\]
D) \[\underline{S}\,{{O}_{2}}\] and \[\underline{S}\,{{O}_{3}}\]
Correct Answer: D
Solution :
| [d] O.N. of N in \[N{{O}_{2}}\] and \[{{N}_{2}}{{O}_{4}}\] is + 4 |
| \[\therefore \] difference is zero. |
| O.N of P in \[{{P}_{2}}{{O}_{5}},\] and \[{{P}_{4}}{{O}_{10}}\] is + 5 |
| \[\therefore \] difference is zero |
| O.N. of N in \[{{N}_{2}}O\] is + 1 and in NO is +2. |
| The difference is 1 |
| O.N. of S in \[S{{O}_{2}},\] is +4 and in \[S{{O}_{3}},\] is + 6. |
| The difference is + 2. |
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