A) \[{{n}_{1}}+\text{ }{{n}_{2}}\]
B) \[{{n}_{2}}-\text{ }{{n}_{1}}\]
C) \[{{n}_{1}}-\text{ }{{n}_{2}}\]
D) \[{{n}_{1}}.{{n}_{2}}\]
Correct Answer: C
Solution :
[c] Balancing charge on both sides \[\Rightarrow {{n}_{1}}-{{n}_{2}}=x\]
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