JEE Main & Advanced Chemistry Redox Reactions / रेडॉक्स अभिक्रियाएँ Sample Paper Topic Test - Redox Reactions

  • question_answer
    The order of increasing O.N. of S in \[{{S}_{8}},\,{{S}_{2}},\,O_{8}^{-2},\,{{S}_{2}}_{3}^{-2}\] is:

    A) \[{{S}_{8}}<{{S}_{2}}O_{8}^{-2}<{{S}_{2}}O_{3}^{-2}<{{S}_{4}}O_{6}^{-2}\]

    B) \[{{S}_{2}}O_{8}^{-2}<{{S}_{2}}O_{3}^{-2}<{{S}_{4}}O_{6}^{-2}<{{S}_{8}}\]

    C) \[{{S}_{2}}O_{8}^{-2}<{{S}_{8}}<{{S}_{4}}O_{6}^{-2}<{{S}_{2}}O_{3}^{-2}\]

    D) \[{{S}_{8}}<{{S}_{2}}O_{3}^{-2}<{{S}_{4}}O_{6}^{-2}<{{S}_{2}}O_{8}^{-2}\]

    Correct Answer: D

    Solution :

    [d] The oxidation number of S are shown below along with the compounds \[\underset{0}{\mathop{{{S}_{8}}}}\,,\underset{+6}{\mathop{\text{  }{{S}_{2}}{{O}_{8}}^{-2}}}\,,\underset{+2}{\mathop{\text{  }{{S}_{2}}{{O}_{3}}^{-2},}}\,\underset{+2.5}{\mathop{\text{  }{{S}_{4}}{{O}_{6}}^{-2}}}\,\] Hence the order of increasing O.N. of S is \[{{S}_{8}}<{{S}_{2}}{{O}_{3}}^{-2}<{{S}_{4}}{{O}_{6}}^{-2}<{{S}_{2}}{{O}_{8}}^{-2}\]


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