JEE Main & Advanced Chemistry Solutions / विलयन Sample Paper Topic Test - Solutions

A solution of 0.2 mole \[Kl\]\[(\alpha =100\,%)\] in 1000 g water freezes at \[{{T}_{1}}{{\,}^{0}}C\]. Now to this solution 0.1 mole \[Hg{{I}_{2}}\] is added and the resulting solution freezes at \[{{T}_{2}}{{\,}^{0}}C\]. Which of the following is correct:

A) \[{{T}_{1}}={{T}_{2}}\]

B) \[{{T}_{1}}>{{T}_{2}}\]

C) \[{{T}_{1}}<{{T}_{2}}\]

D) Nothing can be predict

Correct Answer: C

Solution :

[c] \[2KI+Hg{{I}_{2}}\to {{K}_{2}}[Hg{{I}_{4}}]\]

\[{{K}_{2}}Hg{{I}_{4}}\xrightarrow[{}]{{}}2{{K}^{+}}+{{[Hg{{I}_{4}}]}^{-2}}\]

2 KI will give 4 ions whereas after mixing of 2 KI we are obtaining only 3 ions.