A) 79.42 g/mol
B) 132.32 g/mol
C) 177.42 g/mol
D) 242.32 g/mol
Correct Answer: C
Solution :
[c] Here: \[\Delta {{T}_{b}}\] = 0.323 K |
w = weight of Anthracene. |
W = weight of chloroform |
\[{{K}_{b}}\]= Molal elevation constant (3.9 K-kg/mol) |
\[m=\frac{{{K}_{b}}\times w\times 1000}{W\times \Delta {{T}_{b}}}=\frac{3.9\times 0.5143\times 1000}{0.323\times 35}\] |
\[=177.42g/mol\] |
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