A) 4 : 1
B) 5 : 2
C) 5 : 1
D) 4 : 15
Correct Answer: C
Solution :
[c] \[\frac{\Delta {{T}_{f}}({{K}_{4}}{{[Fe(CN)]}_{6}}}{\Delta {{T}_{f}}\,\text{sugar}}=\frac{5}{1}\]You need to login to perform this action.
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