JEE Main & Advanced Chemistry Structure of Atom / परमाणु संरचना Sample Paper Topic Test - Structure of Atom

  • question_answer
    The ionization energy of hydrogen atom (in the ground state) is x kJ. The energy required for an electron to jump from 2nd orbit to the \[{{3}^{rd}}\] orbit will be

    A) x/6

    B) 5x

    C) 7.2 x    

    D) 5x/36

    Correct Answer: D

    Solution :

    [d] \[{{(IE)}_{H}}={{E}_{\infty }}-{{E}_{1}}=-{{E}_{1}}=x\] volt
    Put       \[{{E}_{1}}=-\frac{K}{{{n}^{2}}}=-\frac{K}{{{1}^{2}}}=-K\]
    \[\therefore \]      \[K=x\]
    \[\Delta E={{E}_{3}}-{{E}_{2}}\]
    \[=-K/{{3}^{2}}-(-K/{{2}^{2}})\]
    \[=K\frac{5}{36}=\frac{5x}{36}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner