A) \[937.3\,\overset{o}{\mathop{A}}\,\]
B) \[1025\,\overset{o}{\mathop{A}}\,\]
C) \[1236\,\overset{o}{\mathop{A}}\,\]
D) None of these
Correct Answer: A
Solution :
| [a] Total number of spectral lines given by |
| \[\frac{1}{2}[n-1]\times n=15\]; \[\therefore \,\,\,n=16\] |
| Thus, electron is excited upto 6th energy level from ground state. Therefore, |
| \[\frac{1}{\lambda }={{R}_{H}}\left[ \frac{1}{{{1}^{2}}}-\frac{1}{{{n}^{2}}} \right]=109737\times \frac{35}{36}\]; |
| \[\lambda =9.373\times {{10}^{-6}}\,cm=937.3\,\overset{o}{\mathop{A}}\,\] |
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