A) 1
B) 0
C) 2
D) 5
Correct Answer: B
Solution :
[b] Electronic configuration of \[Z{{n}^{2+}}\] ion is \[1{{s}^{2}}2{{s}^{2}}\]\[2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{10}}\] so no electron in 4s orbitals.
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