A) \[{{T}_{f}}=\frac{7}{3}{{T}_{0}}\]
B) \[{{T}_{f}}=\frac{3}{2}{{T}_{0}}\]
C) \[{{T}_{f}}=\frac{5}{2}{{T}_{0}}\]
D) \[{{T}_{f}}=\frac{3}{7}{{T}_{0}}\]
Correct Answer: B
Solution :
[b] When two gases are mixed together then Heat lost by the Helium gas = Heat gained by the Nitrogen gas |
\[{{\mu }_{B}}\times {{({{C}_{v}})}_{He}}\times \left( \frac{7}{3}{{T}_{0}}-{{T}_{f}} \right)={{\mu }_{A}}\times {{({{C}_{v}})}_{N2}}\times ({{T}_{f}}-{{T}_{0}})\] |
\[1\times \frac{3}{2}R\times \left( \frac{7}{3}{{T}_{0}}-{{T}_{f}} \right)=1\times \frac{5}{2}R\times ({{T}_{0}}-{{T}_{f}})\] |
By solving we get \[{{T}_{f}}=\frac{3}{2}{{T}_{0}}\] |
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