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  5. Thermometry, Calorimetry & Thermal Expansion

JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Sample Paper Topic Test - Thermometry, Calorimetry & Thermal Expansion

  • question_answer
    A constant volume gas thermometer shows pressure reading of 50 cm and 90 cm of mercury at \[0{}^\circ C\] and \[100{}^\circ C\] respectively. When the pressure reading is 60 cm of mercury, the temperature is

    A) \[25{}^\circ C\]                        

    B) \[40{}^\circ C~\]

    C) \[15{}^\circ C\]            

    D) \[{{12.5}^{o}}C\]

    Correct Answer: A

    Solution :

    \[t=\frac{\left( {{P}_{1}}-{{P}_{0}} \right)}{\left( {{P}_{100}}-{{P}_{0}} \right)}\times 100{}^\circ C\]
    \[=\frac{\left( 60-50 \right)}{\left( 90-50 \right)}\times 100=25{}^\circ C\]


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