A) \[\frac{\mu p}{mg}\]
B) \[\frac{\mu mg}{p}\]
C) \[\mu mgp\]
D) \[\frac{p}{\mu mg}\]
Correct Answer: D
Solution :
| [d] \[\therefore P=F.V=constant\] |
| When \[F=\mu mg\] net force on block becomes zero, i.e., it has maximum or terminal velocity |
| \[\therefore \] \[p=(\mu mg){{V}_{\max }}\] |
| \[\therefore \] \[{{V}_{\max }}=\frac{P}{\mu mg}\] |
You need to login to perform this action.
You will be redirected in
3 sec
