A) 2-methylbut-2-enoic acid
B) 3-methylbut-2-enoic acid
C) 3-methylbut-3-enoic acid
D) 2-methylbut-3-enoic acid
Correct Answer: B
Solution :
\[\underset{3-methylbut-2-enoic\,acid}{\mathop{{{H}_{3}}\overset{4}{\mathop{C}}\,-\overset{C{{H}_{3}}}{\mathop{\overset{3|}{\mathop{C}}\,}}\,=\overset{_{H}}{\mathop{\overset{2|}{\mathop{C}}\,}}\,-\overset{1}{\mathop{C}}\,OOH}}\,\] [\[\because \]Order of preference: \[COOH>(=)>\text{alkyl}\] group.]You need to login to perform this action.
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