JEE Main & Advanced AIEEE Paper (Held On 11 May 2011)

  • question_answer
    The molality of a urea solution in which 0.0100 g of urea, \[[{{(N{{H}_{2}})}_{2}}CO]\]is added to \[0.3000\,d{{m}^{3}}\]of water at STP is:

    A)  \[5.55\times {{10}^{-4}}\]

    B)  \[33.3m\]

    C) \[3.33\times {{10}^{-2}}m\]

    D) \[0.55m\]

    Correct Answer: A

    Solution :

                                    Molality\[=\frac{0.01/60}{0.3}=\frac{0.01}{60\times 0.3};\]           \[d=1\,g/ml\]                 \[=5.55\times {{10}^{-4}}m\]


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