A) \[N\le 100\]
B) \[100<N\le 140\]
C) \[140<N\le 190\]
D) \[N>190\]
Correct Answer: A
Solution :
\[^{10}{{C}_{3}}{{-}^{6}}{{C}_{3}}\] \[=\frac{10\times 9\times 8}{6}-\frac{6\times 5\times 4}{6}=120-20=100\]You need to login to perform this action.
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