A) \[\alpha -\beta \]
B) \[\frac{\alpha -\beta }{100}\]
C) \[\beta -\alpha \]
D) \[\frac{\alpha -\beta }{200}\]
Correct Answer: B
Solution :
Let A.P. be a, a + d, a + 2d, ....... \[{{a}_{2}}+{{a}_{4}}+.....+{{a}_{200}}=\alpha \] \[\Rightarrow \]\[\frac{100}{2}[2(a+d)+(100-1)d]=\alpha \] ?(i) and\[{{a}_{1}}+{{a}_{3}}+{{a}_{5}}+.....+{{a}_{199}}=\beta \] \[\Rightarrow \]\[\frac{100}{2}[2a+(100-1)d]=\beta \] ?.(ii) on solving (i) and (ii) \[d=\frac{\alpha -\beta }{100}\]You need to login to perform this action.
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