A) \[C{{H}_{3}}\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,HCOOH\]
B) \[C{{H}_{2}}\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,{{H}_{2}}COOH\]
C) \[C{{H}_{2}}=CHCOOH\]
D) \[\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{C}}\,{{H}_{2}}\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,HCOOH\]
Correct Answer: C
Solution :
\[C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow[\begin{smallmatrix} \,\,\,\,\,\,\,\,\,\,\,\,\,\text{Red P} \\ \left( \text{HVZ reaction} \right) \end{smallmatrix}]{C{{l}_{2}}}C{{H}_{3}}\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{C}}\,HCOOH\] \[\xrightarrow[\left( \text{elimination} \right)]{\text{Alcoholic KOH}}\underset{\text{Acrylic acid}}{\mathop{C{{H}_{2}}=CHCOOH}}\,\]
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