A) \[PC{{l}_{5}}(g)\underset{{}}{\leftrightarrows}PC{{l}_{3}}(g)+C{{l}_{2}}(g)\]
B) \[{{N}_{2}}(g)+3{{H}_{2}}(g)\underset{\,}{\leftrightarrows}2N{{H}_{3}}(g)\]
C) \[{{N}_{2}}(g)+{{O}_{2}}(g)\overset{\,}{leftrightarrows}2NO(g)\]
D) \[S{{O}_{2}}C{{l}_{2}}(g)\underset{\,}{\leftrightarrows}S{{O}_{2}}(g)+C{{l}_{2}}(g)\]
Correct Answer: C
Solution :
Change in volume affects number of mole per unit volume and move in the direction which undo the change. \[{{N}_{2}}(g)+{{O}_{2}}(g)\overset{{}}{leftrightarrows}2NO(g)\] number of moles of reactants and products are equal.
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