A) \[0.1\] V
B) 8 V
C) 2 V
D) \[0.2\] V
Correct Answer: A
Solution :
Potential difference between two points in an electric field is \[{{V}_{A}}-{{V}_{B}}=\frac{W}{{{q}_{0}}}\] where, W is work done by moving charge \[{{q}_{0}}\] from point A to B. So. \[{{V}_{A}}-{{V}_{B}}=\frac{2}{20}\](here, \[W=2\,J,{{q}_{0}}=20C\]) \[=0.1\,V\]
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