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JEE Main & Advanced AIEEE Solved Paper-2002

  • question_answer
    \[MnO_{4}^{-}\] is a good oxidising agent in different medium changing to                    \[MnO_{4}^{-}\]              \[\xrightarrow{{}}M{{n}^{2+}}\]                                    \[\xrightarrow{{}}MnO_{4}^{2+}\]                                    \[\xrightarrow{{}}Mn{{O}_{2}}\]                                    \[\xrightarrow{{}}M{{n}_{2}}{{O}_{3}}\] Changes    in    oxidation    number respectively are   AIEEE  Solved  Paper-2002

    A) 1, 3, 4, 5      

    B)                           5, 4, 3, 2  

    C)           5, 1, 3, 4                  

    D)           2, 6, 4, 3

    Correct Answer: C

    Solution :

                       \[\overset{+7}{\mathop{M}}\,nO_{4}^{-}\xrightarrow{{}}M{{n}^{2+}}\] change 5                    \[\xrightarrow{{}}\overset{+}{\mathop{M}}\,\overset{6}{\mathop{n}}\,O_{4}^{2-}\] change 1                    \[\xrightarrow{{}}\overset{+}{\mathop{M}}\,\overset{4}{\mathop{n}}\,{{O}_{2}}\] changes 3                    \[\xrightarrow{{}}\overset{+}{\mathop{M}}\,{{\overset{3}{\mathop{n}}\,}_{2}}{{O}_{3}}\] change 4


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