question_answer

Moment of inertia of a circular wire of mass M and radius R about its diameter is   AIEEE  Solved  Paper-2002

A) \[M{{R}^{2}}/2\]

B)           \[M{{R}^{2}}\]     

C)                           \[2M{{R}^{2}}\]   

D)           \[M{{R}^{2}}/4\]

Correct Answer: A

Solution :

Moment of inertia of circular wire about its axis is \[M{{R}^{2}}\]. Consider two diameters \[XX'\] and \[YY'\] moment of inertia about any of this diameter is same let us say \[l\].              From perpendicular axis theorem,              \[l+l=M{{R}^{2}}\]                                    \[l=\frac{M{{R}^{2}}}{2}\]