A) The conjugate base of \[{{H}_{2}}PO_{4}^{-}\] is \[HPO_{4}^{2-}\]
B) \[pH+pOH=14\] for all aqueous solutions
C) The pH of \[1\times {{10}^{-8}}M\]HCl is 8
D) 96,500 coulombs of electricity when passed through a \[CuS{{O}_{4}}\] solution deposit 1g equivalent of copper at the cathode
Correct Answer: C
Solution :
In \[1\times {{10}^{-8}}\] M HCI solution, \[{{H}_{2}}O\] is also present which also undergoes self ionisation \[{{H}_{2}}O{{H}^{+}}O{{H}^{-}}\] \[{{10}^{-7}}\] M at \[{{25}^{o}}C\] If it is taken simply even without common ion effect, higher concentration must be considered which is \[{{10}^{-7}}\] M but \[{{H}^{+}}\] from HCI decreases self ionisation which further decrease constantly, hence, there is \[[{{H}^{+}}]\] from \[{{H}_{2}}O\]. Hence, net concentration must be smaller than\[{{10}^{-7}}\]M. Therefore, it is acidic.
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