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JEE Main & Advanced AIEEE Solved Paper-2003

  • question_answer
    The length of a simple pendulum executing simple harmonic motion is increased by 21%. The percentage increase in the time period of the pendulum of increased length is     AIEEE  Solved  Paper-2003

    A) \[11%\]                               

    B) \[21%\]                               

    C)       \[42%\]                               

    D)       \[10.5%\]

    Correct Answer: D

    Solution :

    The time period of simple pendulum is given by                                 \[T=2\pi \sqrt{\frac{l}{g}}\] \[\Rightarrow \]   \[\frac{\Delta T}{T}=\frac{1}{2}\frac{\Delta \,l}{l}\]          (differentiating) Given,       \[\frac{\Delta \,l}{l}=\] 21% \[\therefore \]  \[\frac{\Delta T}{T}=\frac{1}{2}\times 21%=10.5%\]


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