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JEE Main & Advanced AIEEE Solved Paper-2003

  • question_answer
    When the current changes from \[+2\] A to \[-2\] A in \[0.05\] s, an emf of 8 V is induced in a coil. The coefficient of self-induction of the coil is     AIEEE  Solved  Paper-2003

    A) \[0.2\] H              

    B)       \[0.4\] H                              

    C) \[0.8\] H                              

    D) \[0.1\] H

    Correct Answer: D

    Solution :

    The induced emf, \[e=-L\frac{di}{dt}=-L\frac{(-2-2)}{0.05}\]                                     \[8=L\frac{(4)}{0.05}\]             \[\therefore \]                      \[L=\frac{8\times 0.05}{4}0.1\,H\]


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