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JEE Main & Advanced AIEEE Solved Paper-2004

  • question_answer
    An ideal gas expands in volume from \[1\times {{10}^{-3}}{{m}^{3}}\]to\[1\times {{10}^{-2}}{{m}^{3}}\]at\[300\text{ }K\]against a constant pressure of\[1\times {{10}^{5}}N{{m}^{-2}}\]. The work done is

    A) \[-\text{ }900\text{ }J\]  

    B)                        \[-900\text{ }kJ\]            

    C)        \[270\text{ }kJ\]           

    D)        \[900\text{ }kJ\]

    Correct Answer: A

    Solution :

    Work done due to change in volume against constant pressure is \[W=-p({{V}_{2}}-{{V}_{1}})\] \[=-1\times {{10}^{5}}N{{m}^{-2}}(1\times {{10}^{-2}}-1\times {{10}^{-3}}){{m}^{3}}\] \[=-900Nm=-900J\]                         \[(1\text{ }Nm=1J)\]


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