A) \[C{{u}_{2}}{{l}_{2}}\]is formed
B) \[Cu{{l}_{2}}\]is formed
C) \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]is oxidized
D) Evolved\[{{I}_{2}}\]is reduced
Correct Answer: B
Solution :
\[CuS{{O}_{4}}+2Kl\xrightarrow{\,}\,\underset{Unstabnle}{\mathop{Cu{{l}_{2}}+{{K}_{2}}S{{O}_{4}}}}\,\] Thusis not formed.You need to login to perform this action.
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