question_answer

If\[(1-p)\]is a root of quadratic equation\[{{x}^{2}}+px\] \[+(1-p)=0,\]then its roots are

A) \[0,1\]                  

B)        \[-1,1\]                

C)        \[0,-1\]                

D)        \[-1,2\]

Correct Answer: C

Solution :

Since,is the root of quadratic equation.                        ...(i) So,satisfies the above equation,   On putting this value of pin Eq. (i), we get